67 lines
2.7 KiB
Python
67 lines
2.7 KiB
Python
# coding=utf-8
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# Copyright 2022-present, the HuggingFace Inc. team.
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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"""Contains utilities to handle datetimes in Huggingface Hub."""
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from datetime import datetime, timezone
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def parse_datetime(date_string: str) -> datetime:
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"""
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Parses a date_string returned from the server to a datetime object.
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This parser is a weak-parser is the sense that it handles only a single format of
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date_string. It is expected that the server format will never change. The
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implementation depends only on the standard lib to avoid an external dependency
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(python-dateutil). See full discussion about this decision on PR:
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https://github.com/huggingface/huggingface_hub/pull/999.
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Example:
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```py
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> parse_datetime('2022-08-19T07:19:38.123Z')
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datetime.datetime(2022, 8, 19, 7, 19, 38, 123000, tzinfo=timezone.utc)
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```
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Args:
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date_string (`str`):
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A string representing a datetime returned by the Hub server.
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String is expected to follow '%Y-%m-%dT%H:%M:%S.%fZ' pattern.
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Returns:
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A python datetime object.
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Raises:
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:class:`ValueError`:
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If `date_string` cannot be parsed.
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"""
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try:
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# Normalize the string to always have 6 digits of fractional seconds
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if date_string.endswith("Z"):
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# Case 1: No decimal point (e.g., "2024-11-16T00:27:02Z")
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if "." not in date_string:
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# No fractional seconds - insert .000000
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date_string = date_string[:-1] + ".000000Z"
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# Case 2: Has decimal point (e.g., "2022-08-19T07:19:38.123456789Z")
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else:
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# Get the fractional and base parts
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base, fraction = date_string[:-1].split(".")
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# fraction[:6] takes first 6 digits and :0<6 pads with zeros if less than 6 digits
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date_string = f"{base}.{fraction[:6]:0<6}Z"
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return datetime.strptime(date_string, "%Y-%m-%dT%H:%M:%S.%fZ").replace(tzinfo=timezone.utc)
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except ValueError as e:
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raise ValueError(
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f"Cannot parse '{date_string}' as a datetime. Date string is expected to"
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" follow '%Y-%m-%dT%H:%M:%S.%fZ' pattern."
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) from e
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